Question

find the zeros of the polynomial of 3 root 3 x square - 19 X + 10 root 3 and verify the relationship between zeros and the coefficient​

Answer 1

Answer:

10/3√3 and √3

Step-by-step explanation:

given polynomial

3√3x^2-19x+10√3=0

3√3x^2-9x-10x+10√3=0

3√3x(x-√3) - 10(x-√3)=0

(3√3x-10)(x-√3)=0

x = 10/3√3 or √3

for verification,

sum of the roots = -b/a

10/3√3 + √3 = -(-19)/3√3

10+9/3√3 = 19/3√3

19/3√3 = 19/3√3

Lhs = Rhs

product of the roots = c/a

10/3√3 x √3 = 10√3/3√3

10/3 = 10/3

Lhs = Rhs

Answer 2

Answer:

$\sqrt{3} \: \: \: \: and \: \: \: \frac{10}{ \sqrt{3} }$