Question

find the zeros of the polynomial P of X equal x square - 25​

Answer 1

Answer:

Step-by-step explanation:

P(x)=x^2-25= 0

X^2=-25

X=√25

X=5

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Values\:of\:x=\pm5}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given :}} \\ \tt: \implies {x}^{2} - 25=0 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Values \: of \: x = ?$

• According to given question :

$\tt: \implies x^{2}-25 = 0 \\ \\ \tt: \implies x^{2} = 25\\\\ \tt:\implies x=\sqrt{25}\\\\ \green{\tt:\implies x=\pm5}$

If the question is-

If the question is-find the zeros of the polynomial P(x),x equal x square - 25.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Values\:of\:x=\frac{1+\sqrt{101}}{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given :}} \\ \tt: \implies x = {x}^{2} - 25 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Values \: of \: x = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies x = {x}^{2} - 25 \\ \\ \tt: \implies {x}^{2} -x - 25 = 0 \\ \\ \bold{Solving \: by \: Quadratic \: formula} \\ \tt: \implies d = {b}^{2} - 4ac \\ \\ \tt: \implies d = { (- 1)}^{2} - 4 \times 1 \times ( - 25) \\ \\ \tt: \implies d = 1 + 100 \\ \\ \tt: \implies d = 61 \\ \\ \tt: \implies x = \frac{ - b \pm \sqrt{d} }{2a} \\ \\ \tt: \implies x = \frac{ - ( - 1) \pm \sqrt{101} }{2 \times 1} \\ \\ \green{\tt: \implies x = \frac{1 \pm \sqrt{101} }{2} }$