Question

find the zeros of the polynomial P of x is equal to 16 X square - 3 x minus 10​

Answer 1

$p(x) = 16 {x}^{2} - 3x - 10 \\ p(0) = 16 ( {0)}^{2} - 3(0) - 10 \\ \: \: \: \: \: \: \: \: \: = 0 - 0 - 10 \\ \: \: \: \: \: \: \: \: \: = - 10 \\ \\ p(1) = 16( {1)}^{2} - 3(1) - 10 \\ \: \: \: \: \: \: \: \: \: = 16 - 3 - 10 \\ \: \: \: \: \: \: \: \: \: = 3 \\ \\ p(2) = 16( {2 {}^{2} ) - 3(2) - 10 } \\ \: \: \: \: \: \: = 16(4) - 6 - 10 \\ \: \: \: \: \: \: = 64 - 6 - 10 \\ \: \: \: \: \: \: = 48$