find the zeros of the polynomial P of x is equal to X + 2 into X + 3
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2
P(x)= (x+2)*(x+3)
Hence zeroes of P(x)=0 are x+2=0 and x+3=0
therefore, x=-2 or -3
Hence zeroes of P(x)=0 are x+2=0 and x+3=0
therefore, x=-2 or -3
Answered by
0
(x+२)×(x+3)
= x2+3x+2x+6
=x2+5x+6
= x2+3x+2x+6
=x2+5x+6
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