Question

find the zeros of the polynomial P of x is equal to x square - 15​

Answer 1

Answer:

$= > X2-15x+50 \\ </p><p></p><p> = > X2-5x-10x+50 \\ </p><p></p><p> = > X(x-5)+10(x-5) \\ \\ </p><p></p><p> = > (X-5) +(x+10) \\ \\ </p><p></p><p></p><p>hope \: it \: hepls \: you</p><p>$

@ARSH❤️❤️

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Values\:of\:x=\pm\sqrt{15}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given :}} \\ \tt: \implies {x}^{2} - 15=0 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Values \: of \: x = ?$

• According to given question :

$\tt: \implies x^{2}-15 = 0 \\ \\ \tt: \implies x^{2} = 15\\\\ \tt:\implies x=\sqrt{15}\\\\ \green{\tt\therefore x=\pm\sqrt{15}}$

If the question is-

If the question is-find the zeros of the polynomial P(x), x is equal to x square - 15.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Values\:of\:x=\frac{1+\sqrt{61}}{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given :}} \\ \tt: \implies x = {x}^{2} - 15 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Values \: of \: x = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies x = {x}^{2} - 15 \\ \\ \tt: \implies {x}^{2} -x - 15 = 0 \\ \\ \bold{Solving \: by \: Quadratic \: formula} \\ \tt: \implies d = {b}^{2} - 4ac \\ \\ \tt: \implies d = { (- 1)}^{2} - 4 \times 1 \times ( - 15) \\ \\ \tt: \implies d = 1 + 60 \\ \\ \tt: \implies d = 61 \\ \\ \tt: \implies x = \frac{ - b \pm \sqrt{d} }{2a} \\ \\ \tt: \implies x = \frac{ - ( - 1) \pm \sqrt{61} }{2 \times 1} \\ \\ \green{\tt: \implies x = \frac{1 \pm \sqrt{61} }{2} }$