Question

Find the zeros of the polynomial p of x is equals to x minus log base 2
the power of 16

Answer 1

Answer:

Note:

1) To find the zeros of a polynomial p(x), equate it to zero. ie, operate on ,

p(x) = 0.

2) The degree of the polynomial decides the number of zeros.

The maximum number of zeros is equal to the degree of the polynomial.

Here,

The given polynomial is;

p(x) = x - log_2(16)

Also,

The degree of given polynomial p(x) is one, thus it will have only one zero.

In order to find the zero of the given polynomial, put p(x) = 0

ie,

=> p(x) = x - log_2(16)

=> 0 = x - log_2(16)

=> 0 = x - log_2(2^4)

=> 0 = x - 4log_2(2)

{ since, log_a(b^c) = clog_a(b) }

=> 0 = x - 4•1

{ since, log_a(a) = 1 }

=> 0 = x - 4

=> x = 4.

Hence,

The zero of the given polynomial is 4.

Answer 2

$\huge\bf{\underline{\green{Solution\: is\: attached\:here.}}}$

Therefore, the zero of the polynomial is 4.