find the zeros of the polynomial p of x=xcube-16
Answers
Answered by
1
Answer:
p(x) = x³- 16
i.e., a = 1, b = 0, c = 0, d = -16
The Sum of zeros = -(b/a)
= -(0/1) = 0.
The Sum of the products of the zeros taken two
at a time = c/a
= 0/1 = 0.
The Product of zeros = -(d/a)
= -(-16/1) = 16.
Similar questions