find the zeros of the polynomial :
p of y equal to 7 Y squared minus 11 by 3 Y - 2 by 3
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Answer:
p (y ) = 7y^2 -11/3y - 2/3
= 21y ^2 -11y -6/3
= 21 y ^2 -11y -2
so now we can find its zeroes easily .
= 21y^2 -14y -3y -2
= 7y ( 3y -2) +1 ( 3y -2)
= ( 7y +1 ) ( 3y -2 )
7y+1 = 0 and 3y -2 =0
y = -1/7 and y = 2/3
.: the zeroes of the given polynomial is -1/7 and 2/3 .
Hope it will helps you . :--)
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