Find the zeros of the polynomial p x is equal to x square minus 7
Answers
Answered by
0
Step-by-step explanation:
Solution :
Given p(x) = x² - 9
Let p(x) = 0
=> x² - 9 = 0
=> x² - 3² = 0
=> ( x + 3 )( x - 3 ) = 0
x + 3 = 0 or x - 3 = 0
x = -3 or x = 3
Therefore
-3 , 3 are zeroes of p(x).
hope it helps
Similar questions