Question

find the zeros of the polynomial p x is equal to x square minus 9

Answer 1

Answer:

p(x) = x²-9 = 0

= x²-(3)²= 0

= (x+3)(x-3) = 0

Hence the roots are +3 & -3

Answer 2

❤❤Hey mate...here is ur ans...❤❤

$p(x) = {x}^{2} - 9 \\ \\ p(x) = {x}^{2} - {3}^{2} \\ \\ p(x) = (x - 3) {}^{2}=0 \\ \\ = > (x + 3)(x - 3) \\ \\ so \: \: the \: \: zeros \: \: of \: \: the \: \: poymomial \\ \: \: p(x) \: \: are \: \: + 3 \: \: and \: \: - 3$

❤❤Hope it helps u...thanks...❤❤