Question

Find the zeros of the polynomial p(x)=root 2 x 2-3x-2 root 2

Answer 1

$p(x) = \sqrt{2} {x}^{2} - 3x - 2 \sqrt{2} \\ \\ p(x) = \sqrt{2} {x}^{2} - 4x + x - 2 \sqrt{2} \\ \\ p(x) = \sqrt{2} x(x - 2 \sqrt{2} ) + 1(x - 2 \sqrt{2} ) \\ \\ p(x) = ( x - 2\sqrt{2} )( \sqrt{2} x + 1)$

$\alpha = 2 \sqrt{2}$

$\beta = \frac{ - 1}{ \sqrt{2} }$

Answer 2

Your answer is down please mark it as brainlist