find the zeros of the polynomial p(x)=(x-2)^2- (x+2)^2
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p(0)=(0-2)^2-(0+2)^2
p(0)=0^2-(2)^2
p(0)=(2)2×2
p(0)=(2)4
p(0)=0^2-(2)^2
p(0)=(2)2×2
p(0)=(2)4
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