Question

Find the zeros of the polynomial :
p(x)=( x - 2 )² - ( x + 2 )²​

Answer 1

Answer:

Step-by-step explanation:

using identity

a²-b²=(a-b)(a+b)

(x-2)² - (x+2)² = (x-2-x-2)(x-2+x+2)

                     =(-4)(2x)

now -8x=0

so, x=0 is the zero of the given quadratic eq.

Answer 2

Hey mate

Here is ur answer

P(x) =x^2-4x+4-(x^2+4x+4)

P(xl=x^2-4x+4-x^2-4x-4

P(x)=-8x

Hope u like it

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