Question

find the zeros of the polynomial p (x)=(x-2)^2-(x+2)^2 plz answer soon .....

Answer 1

$( {x - 2})^{2} - {(x + 2)}^{2} = 0 \\ ={x}^{2} + 4 - 4x - ( {x}^{2} + 4 + 4x) = 0 \\ x ^{2} + 4 - 4x - {x}^{2} - 4 - 4x = 0 \\ - 8x = 0 \\ x = 0$
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