Question

find the zeros of the polynomial p(x)= x^2-2x-3​

Answer 1

x² - 2x - 3 = 0

x² +x - 3x - 3 = 0

x(x + 1) - 3(x + 1) = 0

x - 3 = 0 x + 1 = 0

x = 3 x = -1

ᴛʜᴀɴᴋ ʏᴏᴜ ●•٠·˙

Answer 2

Answer:

p(x)=3

Step-by-step explanation:

p(3)=3^3-2×3-3

=9-6-3

=9-9

=0