Question

find the zeros of the polynomial p(x)= x^3+4x^2+x-6​

Answer 1

Step-by-step explanation:

putting the value of X= -2

p(X)= x^3+4x^2+x-6

p(-2)= (-2)^3+4(-2)^2+(-2)-6

p(-2)= -8 + 16 - 8

p(-2)= -16+16= 0

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