Question

find the zeros of the polynomial.p(x)=x^4-16​

Answer 1

Answer:

$p(x) = 0$

$x {}^{4} - 16 = 0$

$x {}^{4} = 16$

$x = \sqrt[4]{16}$

$x = + 2 \: \: or \: \: - 2$

$i \: hope \: this \: answer \: may \: help \: you$

Answer 2

p(x) = 0p(x)=0

x {}^{4} - 16 = 0x

4

−16=0

x {}^{4} = 16x

4

=16

x = \sqrt[4]{16}x=

4

16

x = + 2 \: \: or \: \: - 2x=+2or−2