Question

find the zeros of the polynomial p(x)=x²-3​

Answer 1

Answer:

$x = +\sqrt{3}, - \sqrt{3}$

Step-by-step explanation:

For zeroes, p(x) = 0

∴ $x^2-3=0$

⇒$x^2=3$

⇒ $x=$ ±$\sqrt{3}$

∴ The roots are $x = +\sqrt{3}, - \sqrt{3}$