Question

Find the zeros of the polynomial : p(x) =x²+3x​

Answer 1

Answer:

Since polynomials f(x)=x2+3x

Here a=1 b=3 c=0

(x)2+(under root 3)2×x

(x-under root 3)(x+under root 3)

There are method to find zeros

à+B=-b/a àB=c/a

Here à=-under root3 B=under root3

à+B=-b/a àB=c/a

under root(-3+3)= undroot(-3×3)=

-3/1 0/1

-3=-3 0=0

ZEROS WILL BE-under root3 , underroot3

Step-by-step explanation:

Answer 2

Answer:

answers r 0 and -3

Step-by-step explanation:

x^2+x=o

x(x+3)=0

x=0 or x+3=0

x=0 or x = -3

therefore x=-3,0