Question

find the zeros of the polynomial p(z) = (4z+x) (z-x)

Answer 1

Answer:

7×4

−22

and

7

88

\frac{ - 11}{14} \: \: and \: \: \frac{88}{7}

14

−11

and

7

88

hope its useful

Answer 2

Answer:

Correct option is

A

4π,−

4

π

Given P(z)=4z

2

−15πz−4π

2

To find out its roots, we have to equate it to zero

4z

2

−15πz−4π

2

=0

4z

2

−16πz+πz−4π

2

=0

4z(z−4π)+π(z−4π)=0

(4z+π)(z−4π)=0

z=4π,−

4

π