find the zeros of the polynomial polynomial and verify the relationship between the zeros and the coefficients 9 x square minus 5 and 5 x square + 2 x
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Answer:
2x^2-9x-45
S=-9
P=-90
-15,+6
= 2 x square + 6x - 15 x - 45
= 2 X ( X + 3) -15(x+3)
=( 2 x-15)( X + 3)
therefore the zeros are x=15/2and x =-3
x=15/ 2 is rejected
therefore X = -3
P(x) =2x^2 -9x -45
P(-3)=2(-3)^2 -9(-3) -45
=2(9) +27 -45
=18 +27 -45
=45 -45
P(-3)=o
therefore x = -3
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