Question

find the zeros of the polynomial
${3x}^{2} - 2x - 7$

Answer 1

$\large{\textbf{\underline{Shridharacharya}}}$
$\large{\textbf{\underline{Method} :}}$



⇒ D = b² - 4ac

⇒ D = (- 2)² - 4(3)(- 7)

⇒ D = 4 + 84

⇒ D = 88



$\bold{x = \frac{- b - \sqrt{d} }{2a} \: and \: \frac{- b + \sqrt{d} }{2a}} \\ \\ \bold{x = \frac{2 - \sqrt{88} }{2 \times 3} \: and \: \frac{2 + \sqrt{88} }{2 \times 3}} \\ \\ \bold{x = \frac{2 - 2 \sqrt{22} }{6} \: and \: \frac{2 + 2 \sqrt{22} }{6}} \\ \\ \bold{x = \frac{1 - \sqrt{22} }{3} \: and \: \frac{1+ \sqrt{22} }{3}}$



$\huge{\textbf{\underline{Conclusion}}}$



• Roots arent real i.e, they are irrational

• Roots can be < 0 and in non terminating and not repeating form.