Question

find the zeros of the polynomial
${8x}^{2} - 4$

Answer 1

hay!!

Dear friend -

hear is ur answer =>

Let => p ( x ) = 8x² - 4 

So,

=>  8x²  = 4

=> x²  = 4/8

=> x² = 1/2

Hence,

x=-1/√2

and x = 1/√2

I hope it's help you

Answer 2

Hope it will be help you