Question

find the zeros of the polynomial
$p(x) = x{2} - x - 6$
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Answer 1

Answer:

We find the zeroes by factorizing the equation x

2

−x−6=0 as follows:

x

2

−x−6=0

⇒x

2

−3x+2x−6=0

⇒x(x−3)+2(x−3)=0

⇒(x+2)(x−3)=0

⇒x+2=0,x−3=0

⇒x=−2,x=3

Hence, the zeroes of the polynomial x

2

−x−6=0 are 3,−2.

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Answer 2

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Question:-

• find the zeros of the polynomial P(x) = x^2 - x -6

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Answer :-

Zeros are :-

✏ x = 1

✏ x = 6

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Step by step explanation:-

$⇒{x}^{2} - x - 6 \\ \\ ⇒ {x}^{2} - (6 - 1)x - 6 \\ \\ ⇒ {x}^{2} - 6x + x - 6 \\ \\ ⇒x(x + 1) - 6(x - 6) \\ \\ ⇒(x + 1)(x - 6)$

Factors are (x+1)(x-6)

➻ x+1=0

x= 1

➻ x-6=0

x =6

So zeros are 1 and 6

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How to find zeros:-

• First factorise by spelling middle term .
• Then solve the factors for zeros

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