Question

Find the zeros of the polynomial x^2+(1/6)x-2=0

Answer 1

Step-by-step explanation:

I hope u get it. If yes then don't forget me to follow.Also mark my answer as brainlist answer...

Answer 2

$\pink{\boxed{\boxed{\boxed{Answer:-}}}}$

Given: The polynomial x^2 + 1/6(x) - 2

To find:  The zeroes of the polynomial and verify the relation between the coefficient and zeroes of the polynomial.

Solution:

Now we have given the polynomial: x^2 + 1/6(x) - 2 = 0

Simplifying it, we get:

               6x^2 + x - 12 = 0

So by splitting middle term, we get:

               6x^2 - 8x + 9x - 12 = 0

Now combining the terms, we get:

               (6x^2 - 8x) + (9x - 12) = 0

               2x(3x - 4) + 3(3x + 4) = 0

               (3x - 4)(2x + 3) = 0

               x = 4/3 or x = -3/2

So verifying it, we get:

Sum of zeroes: 4/3 - 3/2 = -1/6

Product of zeroes: 4/3 x (-3/2) = -2

Hence verified.

Answer:

                So the zeroes of the polynomial are 4/3 and -3/2.

$<marquee behaviour-move><font color="orange"><h1>#itzcutiepie </h1></marquee>$

$\pink{\boxed{\boxed{\boxed{15 Thanks +Follow =Inbox}}}}$,,

,