Find the zeros of the polynomial x^2 - 17... with proper steps plsss
Answers
Answered by
17
Step-by-step explanation:
The given polynomial is
p(x)=x^2-17x+30
To find the zeroes, equate the polynomial equal to zero.
p(x)=0
x^2-17x+30=0
x^2-15x-2x+30=0
x(x-15)-2(x-15)=0
(x-15)(x-2)=0
x=15,2
Therefore the zeroes of the given polynomial are 15 and 2.
Answered by
1
Answer:
given x^2 -17
(x+√7) (t-√7)
x+√7=0
x= -√7.........1 zeroes
x-√7=0
x=√7...........2 zeroes
thank you
hope it help you
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