Question

find the zeros of the polynomial :
x^2 +4x + 3​

Answer 1

Answer:

x = -1, x = -3

Step-by-step explanation:

x^2 + 4x + 3 = 0

x^2 + 3x + x +3 = 0

x(x+3) + 1(x+3) = 0

(x+1) (x+3) =0

x = -1 , x = -3

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Answer 2

Answer:

Step-by-step explanation:

Let P(x) = x^2 +4x + 3.

Zero of the polynomial is the value of x For which P(x) =0.

putting P(x) = 0

x^2 + 4x + 3 = 0

Now we find the roots using splitting the middle term method :

x^2 + x + 3x +3 = 0

x(x+3) + 3(x+1)=0

(x+3)(x+1) =0

So the value of x is -3 ,-1

Hence , zeros of polynomial x^2 +4x + 3​ are -3 , -1