Question

find the zeros of the polynomial x^2+4x+4​

Answer 1

Answer:

$x {}^{2} + 4x + 4 = 0 \\ \\ x {}^{2} + 2x + 2x + 4 =0 \\ \\ x(x + 2) + 2(x + 2) = 0\\ \\ (x + 2)(x + 2) = 0 \\ \\ \boxed{ \bf x = - 2 \: or \: x = - 2}$

Answer 2

${x}^{2} + 4x + 4$

${x}^{2} + 2x + 2x + 4$

$x(x + 2) + 2(x + 2)$

$(x + 2)(x + 2)$

so zeros of polynomial is -2