Question

Find the zeros of the polynomial x^2+5x+4

Answer 1

Hey mate, here is your answer -:)

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${x}^{2} + 5x + 4 \\ {x}^{2} + (4 + 1)x + 4 \\ {x}^{2} + 4x + x + 4 \\ x(x + 4) + 1(x + 4) \\ (x + 1)(x + 4) \\ \\ x + 1 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 4 = 0 \\ \: \: \: \: \: \: \: \: x = - 1 \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: x = - 4$
The zeros of the polynomial are -1 and -4

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HOPE it helps to you!!

Answer 2

Here is your solution

$= x {}^{2} + 5x + 4 \\ = x {}^{2} + 4x + x + 4 \\ = x(x + 4) + 1(x + 4) \\ = (x + 4)(x + 1)$
Now

x+4=0
x= - 4

or

x+1=0
x= -1

hope it help you