Question

find the zeros of the polynomial X^2 + X - 12 and verify the relation between zeros of the polynomial and coefficients of the polynomial​

Answer 1

we have to find the zeroes of the quadratic

polynomial, x2 + x - 12.

x2 + x - 12 = 0

= x2 + 4x - 3x - 12 = 0

x(x +4) -3(x + 4) = 0

- (x - 3)(x + 4) = 0

X= 3,-4

sum of zeroes = - coefficient of x/coefficient of x?

sum of zeroes = 3-4 = -1

-coefficient of x/coefficient of x? = -1/1 = -1

LHS = RHS

product of zeroes = constant/coefficient of x2

product of zeros = 3 x -4 = -12

constant/coefficient of x2 = -12/1 = -12

LHS = RHS

hence verified

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