Question

find the zeros of the polynomial -x^2+x+6

Answer 1

Step-by-step explanation:

-x²+x+6=0

now changing sign of whole eq

x²-x-6=0

x²-x=6

x=6

Answer 2

Answer:

$- {x}^{2} + x + 6 =-{x}^{2}+ 2x+ \\ 3x+6 \\ x( x - 3) + 2(x - 3) \\ = (x - 3).( x + 2) \\ x = 3 \: \: x = ( - 2) \\ zero \: polynomial \: are \: (3) \: and \: ( - 2)$

I hope it help you