Math, asked by hemantarya28409, 1 year ago

Find the zeros of the polynomial x^2+x-p (p+1)

Answers

Answered by LordDinkan
489
Hi factorise it.
 {x}^{2}  + x - p(p + 1) = 0 \\  {x}^{2}  + (p + 1)x - px - p(p + 1) = 0 \\ x(x - p) + (p + 1)(x - p) = 0 \\ (x + p + 1)(x - p) = 0 \\
Therefore x=p or x = -(p+1)
Hope this helps.
Answered by bestanswers
166

Answer:

Find zeros of the equation x^2 + x-p(p+1)

Step-by-step explanation:

So first step would be to make it in the form of a quadratic equation in simple form.

We get,   x^2 + x-p (p+1) = 0

X^2 + x – p^2 –p = 0

X(x + 1) –p(p-1) = 0

So it is obvious that either x (x + 1) = 0 or – p (p-1) = 0

So x = 0 or p = 0.

Now for verification we plug in values of x = 0 or p = 0 in equations we get..

0 + 0 -0(0+1) = 0

0 + 0 – 0 – 0 = 0

L.H.S = R.H.S.

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