Question

find the zeros of the polynomial x cube minus 7 x + 6

Answer 1

Hey user here's ur answer :-)

please mark it as branliest

Answer 2

${x}^{3} - 7x + 6 \\ \alpha + \beta + \gamma = \frac{ - b}{a} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} \\ \alpha \beta \gamma = \frac{ - d}{a}$