Question

find the zeros of the polynomial X square - 4 x + 3​

Answer 1

Answer:

x²-4x+3

=x²-3x-x+3=0

=x(x-3)-1(x-3)

(x-1)(x-3)

X=| x=3 are roots of polynomial

Answer 2

The zeros of the polynomial are x = 1 and x = 3

Solution:

Given that,

$x^2 - 4x + 3$

We have to find the zeros of the polynomial

$x^2 - 4x + 3 = 0\\\\Split\ the\ middle\ term\\\\x^2 -x-3x + 3 = 0\\\\\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(x^2-x\right)+\left(-3x+3\right) = 0\\\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-x\\\\x(x- 1) + (-3x + 3) = 0\\\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-3x+3\mathrm{:\quad }\\\\x(x-1) - 3(x - 1) = 0\\\\\mathrm{Factor\:out\:common\:term\:}x-1\\\\\left(x-1\right)\left(x-3\right) = 0\\\\Thus\ the\ zeros\ are\\\\x = 1\\\\x=3$

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