find the zeros of the polynomial X square + 7 x + 10
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x=-5
x=-2
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ANSWER:
- Zeroes are (-2) and (-5)
GIVEN:
- P(x) = x²+7x+10
TO FIND:
- Zeroes of the given polynomial.
SOLUTION:
=> x²+7x+10 = 0
=> x²+5x+2x+10 = 0
=> (x²+5x)+(2x+10) = 0
=> x(x+5)+2(x+5) = 0
=> (x+5)(x+2) = 0
Either (x+5) = 0
=> x = (-5)
Either (x+2) = 0
=> x = (-2)
Verification:
P(x) = x²+7x+10
Putting x =(-5)
=> P(-5) = (-5)²+7(-5)+10
=> P(-5) = 25-35+10
=> P(-5) = 0
Putting x = (-2)
=> P(-2) = (-2)²+7(-2)+10
=> P(-2) = 4-14+10
=> P(-2) = 0
NOTE:
some important formulas:
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
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