Question

find the zeros of the polynomial x square minus 7 by 2 X + 3 by 2​

Answer 1

Step-by-step explanation:

${x}^{2} - \frac{7}{2} x + \frac{3}{2} = 0$

$\frac{2 {x}^{2} - 7x + 3}{2} = 0$

$2 {x}^{2} - 7x + 3 = 0$

$2 { x}^{2} - 6x - x + 3 = 0$

$2x(x - 3) - 1(x - 3) = 0$

$(x - 3)(2x - 1) = 0$

$either \: (x - 3) = 0 \: or \: (2x - 1) = 0$

$x = 3 \: \: or \: x = \frac{1}{2}$

Answer 2

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Step-by-step explanation: