find the zeros of the polynomial x2-100x+2500 using it graphs
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Answered by
3
x^2-100x+2500
x^2-50x-50x+2500
x(x-50)-50(x-50)
(x-50)(x-50)
x=50,50
x^2-50x-50x+2500
x(x-50)-50(x-50)
(x-50)(x-50)
x=50,50
Answered by
3
x2-100x +2500
x2-50x -50x+2500
x(x-50)-50(x-50)
(x-50)(x-50)
x=50,50
x2-50x -50x+2500
x(x-50)-50(x-50)
(x-50)(x-50)
x=50,50
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