Question

Find the zeros of the polynomial x2-15x-34.

Answer 1

Answer:

17  and -2

Step-by-step explanation:

f(x) = X^2 - 15x -34 =0

0 =x^2 -17x +2x -34

0= x (x -17) +2 (x - 17)

0 =( x -17)(x +2)

X =17 or x = - 2

hope this helps.

Answer 2

The zeros of the polynomial are 17 or -2

Step-by-step explanation:

Given:

equation = x²-15x-34

To find:

zeros of the polynomial or the equation

Solution:

Let the polynomial  x²-15x-34 be p(x)

We can do that using two ways. The quadratic method or the factorization method

Let's use the quadratic method

here, the equation has to be in the form ax²+bx+c=0

where $x= \frac{-b\ \±\sqrt{ b\²-4ac}}{2a}$

here, a = 1, b= -15, c= -34

∴ $x= \frac{-(-15)\ \±\sqrt{ (-15)\²-4(1)(-34)}}{2(1)}$

∴ $x= \frac{(15)\ \±\sqrt{ 225- (-136)}}{2}$

∴ $x= \frac{15\ \±\sqrt{361}}{2}$

∴ $x= \frac{15\ \± 19} {2}$

∴ $x= \frac{15\ + 19} {2} or \ x= \frac{15\ - 19} {2}$

∴ $x= \frac{34} {2} or \ x= \frac{-4} {2}$

∴ $x= 17 \ or \ x= -2$

∴ x = 17 or x = -2

Hence, the zeros of the polynomial  x²-15x-34 are 17 or -2

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