Question

find the zeros of the polynomial x2+2x-195

Answer 1

P (x) = x2 + 2x - 195.
P(x) = 0.
x2 + 2x - 195 = 0.
Now by splitting of middle term we get:-
x2 - 13x + 15x - 195 = 0.
x ( x - 13 ) + 15 ( x - 13 ) = 0.
( x + 15 ) ( x - 13 ) = 0.
x = -15 and 13 are the zeros of the polynomial.

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Answer 2

Answer:

13 and -15 are the zeros of the polynomial.

Step-by-step explanation:

Given the polynomial

$x^2+2x-195$

we have to find the zeroes of the polynomial.

$x^2+2x-195$

To find zeroes we have to put the above polynomial equals to 0 then solve for x

$x^2+2x-195=0$

Now by middle term splitting method

$x^2-13x+15x-195=0$

$x(x - 13) + 15(x - 13)=0$

$(x-13)(x-15)=0$

$x-13=0, x-15=0$

x=13, x=15

which are the zeros of the polynomial.