Question

Find the zeros of the polynomial
X²-2x-8

Answer 1

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4) (x+2)

Answer 2

Step-by-step explanation:

${x }^{2} - 4x + 2x - 8 \\ x(x - 4) + 2(x - 4) \\( x + 2)(x - 4) \\ x = - 2 \: and \: + 4$

here u go

hope it helps