Find the zeros of the polynomial x2 – 2x - 8
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f(x)=x^2-2x-8
=x^2-4x+2x-8
=x(x-4)+2(x-4)
=(x+2) (x-4)
zeros of the polynomials are -2 and 4
sum of the zeros = - coefficient of x/ coefficient of x
=-2+4=(-2)/1
2=2
product of the zeros=constant term/coefficient of x^2
-2×4=-8/1
-8 = -8
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