Find the zeros of the polynomial x2-2x-8 and verifythe reltionship between its zeros and coefficients.
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x²-2x-8
p+q= -2
pq= -8
p= -4 and q= -2
x²-4x-2x-8
x(x-4)-2(x+4)
(x-2)(x-4)
x=2 and x=4
Sum of zeroes = -Coefficient of x/ Coefficient of x²
Sum of zeroes= -(-2)/1
Sum of zeroes= 2
Product of zeroes= Constant/ Coefficient of x²
Product of zeroes= -8/1
Product of zeroes= -8
p+q= -2
pq= -8
p= -4 and q= -2
x²-4x-2x-8
x(x-4)-2(x+4)
(x-2)(x-4)
x=2 and x=4
Sum of zeroes = -Coefficient of x/ Coefficient of x²
Sum of zeroes= -(-2)/1
Sum of zeroes= 2
Product of zeroes= Constant/ Coefficient of x²
Product of zeroes= -8/1
Product of zeroes= -8
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