Question

find the zeros of the polynomial x²-2x-80and verify the relationship between zeros and the coefficient.​

Answer 1

Step-by-step explanation:

$x {}^{2} - 2x - 8.$

$x {}^{2} - 2x - 80 = 0 \\ x {}^{2} - 10x + 8x - 80 = 0 \\ x(x - 10) + 8(x - 10) = 0 \\(x - 10)(x + 8) = 0 \\ x1 = 10 \: or \: x2 = - 8 \\ \\ now \: relation \\ x1 + x2 = 2 \: and \: - \frac{b}{a} = 2 \\ and \\ x1 \times x2 = - 80 \: and \: \frac{c}{a} = - 80$

This is the right solution.

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