Question

Find the zeros of the polynomial x²-3 and verify the relationship between the zeros and the coefficients.​

Answer 1

Answer:

Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.

Step-by-step explanation:

Hope it helped!!!!!

Answer 2

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=>X²-3=0

=>x²=3

=>x=+√3 or -√3

Now next let's VERIFY it:

x²-3

=>(√3)²-3

=>3-3

=>0

=>x²-3

=>(-√3)²-3

=>3-3

=>0

Hence, VERIFIED.

Hope it helps!!!