Question

Find the zeros of the polynomial x2+4√3v-15

Answer 1

Answer:

Hi friend,

f(v)=v²+4√3v-15

=v²+5√3v-√3v-15

=v(v+5√3)-√3(v+5√3)

=(v-√3)(v+5√3)

so,√3,-5√3 are the zeros of the given polynomial.

I hope this will help u ;)

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