Question

Find the zeros of the polynomial x2-4 and verify the relationship between
zeroes and its coefficients.​

Answer 1

Step-by-step explanation:

x2-4 =0

X2 = 4

x =4/2

x = 2

2 is the cofficient of x

Answer 2

Answer:

please mark as brainliests .

Step-by-step explanation:

x²-4

let, p(x)=0

x²-4=0

(x)²-(√4)²=0

(x+√4) (x-√4)=0

x=-√4 , x=√4

$\alpha = - \sqrt{4} \\ \beta = \sqrt{4}$

here, a=1 , b=0 , c=-4

$\alpha + \beta = \frac{ - b}{a}$

-√4+√4=-0/1

0=0

hence,

LHS=RHS

$\alpha \times \beta = \frac{c}{a}$

-√4×√4=-4/1

-4=-4

hence,

LHS=RHS

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.hope it's help you.