Find the zeros of the polynomial x2+6x+2.
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If α,β are the zeros of the polynomial x2+6x+2 then (1α+1β)=? Solution : α+β=-6andαβ=2. ∴(1α+1β)=(α+β)αβ=-62=-3.
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Answer:
-3+2root 7 and -3-2 root 7
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