Question

find the zeros of the polynomial x²+x-p(p+1). plss explain it also in a easy way ​

Answer 1

Answer:

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Answer 2

Answer:

Given polynomial equation x2+x-p (p+1)

x2+x-p(p+1)=0

On factorising we get,

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, and x= p

The zeros of polynomial are: p-1 and p

explanation

x2 +x−p(p+1)=0

x2 +x−p(p+1)=0⇒x2+(p+1)x−px−p(p+1)=0

x2 +x−p(p+1)=0⇒x2+(p+1)x−px−p(p+1)=0⇒x(x+(p+1))−p(x+(p+1))=0

x2 +x−p(p+1)=0⇒x2+(p+1)x−px−p(p+1)=0⇒x(x+(p+1))−p(x+(p+1))=0⇒(x−p)(x+(p+1))=0

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⇒x−p=0 OR x+(p+1)=0

⇒x−p=0 OR x+(p+1)=0⇒x=p OR x=−(p+1)