Question

find the zeros of the polynomial x³-2x²-x+2​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER

P(0)= O^3 -2(0^2)-0+2

= 0-2-0+2

anwer will be 0

hope this help u

Answer 2

Let p(x)=x³−2x³−x+2

The coefficient of the leading term is 1 and the constant term is 2.

Also the factors of 2 are 1 and 2.

So the possible integral zeroes of p(x) are ±1 and ±2.

p(1)=(1)³ −2(1)³ −(1)+2

=1−2−1+2=0

⇒1 is a zero of p(x).

Also

p(−1)=(−1)³−2(−1)³−(−1)+2

=−1−2+1+2=0

⇒−1 is a zero of p(x).

p(2)=(2)³ −2(2)² −(2)+2

=8−8−2+2=0

⇒2 is a zero of p(x).

∴ −1, 1 and 2 are zeroes of p(x).