Question

find the zeros of the polynomial x3-7x2+36 =0 given that one zero is the double of the other​

Answer 1

Answer:

3&6

Step-by-step explanation:

first is prime factorization of 36

it gives 3and 2 as prime factors

insert values 3 ,2 respectively in equation

check the eq.if value of x is 3 so equation becomes zero.

hence

3is the one zero

and as given another zero is double

so 3&6are zeroes of equation

Answer 2

Answer:

3 and 6

Step-by-step explanation:

Prime factorisation of the constant (36) = 2x2x3x3

Let us now substitute the value of p(x) by p(3) as 3 is the greatest number in the prime factorisation of 36.

p(x) = x3-7x2+36

p(3) = 3^3 - 7(3^2) + 36

      =) 27 - 7(9) + 36

      =) 63 - 63

      =) 0

Therefore the second zero of the polynomial is 6 as (6=3x2)